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Question

A solution containing $B r^{-}$ ions is treated with each of the following. Which of these will not liberate bromine gas?

C l_{2}

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H I

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I_{2}

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S O_{3}

(in acidic medium)

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Solution

The correct options are
B $H I$
C $I_{2}$
$C l_{2}$ and $S O_{3}$ being stronger oxidising agent, oxidise $B r^{-}$ to $B r_{2}$ gas.
$2 B r^{-} + C l_{2} \to B r_{2} + 2 C l^{-}$
$S O_{3} \to S O_{2} + [O]$
$2 B r^{-} + 2 H^{+} [O] \Rightarrow B r_{2} + H_{2} O$
$2 B r^{-} + S O_{3} + 2 H^{+} \to B r_{2} + H_{2} O + S O_{2}$
HI being reducing agent and $I_{2}$ being weak oxidising agent (comes after bromine) don't liberate bromine from $B r^{-}$ .

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