A solution containing magnesium ions $(M g^{2 +})$ , iron (II) ions $(F e^{2 +})$ and copper ions $(C u^{2 +})$ . On passing an electric current through this solution which ions will be the first to be discharged at the cathode? Write the equation for the cathode reaction.

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Solution

The ions which are present lower in the electrochemical series get discharged at the electrode in preference to the ions which are above it.
So, the Copper ion $(C u^{2 +})$ will get discharged at the cathode.
Copper has two electrons less, so it will accept two electrons. The cathode reaction is $C u^{2 +} + 2 e^{-} \to C u$

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A solution containing magnesium ions(Mg2+), iron (II) ions (Fe2+)and copper ions(Cu2+). On passing an electric current through this solution which ions will be the first to be discharged at the cathode? Write the equation for the cathode reaction.

A solution containing magnesium ions $(M g^{2 +})$ , iron (II) ions $(F e^{2 +})$ and copper ions $(C u^{2 +})$ . On passing an electric current through this solution which ions will be the first to be discharged at the cathode? Write the equation for the cathode reaction.