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Standard IX

Biology

Monosaccharides

A solution co...

Question

A solution containing several unknown cations is treated with dil. $H C l$ and a ppt. forms. The ppt. is filtered and the filtrate at pH $1.0$ is treated with $H_{2} S$ , no ppt. forms. At pH $8.0, H_{2} S$ causes the formation of a ppt., the filtrate from which gives no ppt. on treatment with $N a_{2} C O_{3}$ . Which group of cations are present in the original solution?
Give your answer as a number with digits as the group number (in ascending order).

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Solution

Since group, I cations reacts with dilute $H C l$ to give a precipitate and cations of group II react with $H_{2} S$ to give a precipitate in acidic medium.
Group III cations give precipitate on reacting with $H_{2} S$ in ammonia medium and group IV cations react with $N a_{2} C O_{3}$ to give a precipitate.
Therefore, cations of group I and group III are present in the original solution.

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