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Concentration Terms

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Question

A solution contains 2.8 moles of Acetone and 8.2 moles of chloroform. Calculate mole fraction of Acetone.

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Solution

Mole fraction of acetone = $\frac{N o . o f m o l e s o f a c e t o e}{N o . o f m o l e s o f c h l o r o f o r m + N o . o f m o l e s o f a c e t o n e} = \frac{2.8}{8.2 + 2.8} = \frac{2.8}{11} = 0.254$

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