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Question

A solution contains 4 g of Na2CO3 and NaCl. 25 mL of this solution requires 50 mL of N10 HCl for complete neutralization. The % composition of mixture is (as nearest integer) :

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Solution

Let mass of Na2CO3 and NaCl in given mixture be a and b g respectively.
a+b=4...(i)
The solution is allowed to react with HCl; only Na2CO3 reacts and thus, Meq. of Na2CO3= Meq. of HCl in 25 mL=50×(110)=5
Meq. of Na2CO3 in 250 mL=(5×250)25=50
or, a1062×1000=50
a=2.65
By (i), b =42.65=1.35
Na2CO3=(2.654)×100=66.25%
and NaCl= 33.75%
So, answer is 34 %.

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