A solution contains non- volatile solute of molecular mass $M_{2}$ . Which of the following can be used to calculate the molecular mass of solute in terms of osmotic pressure ?

M_{2} = [\frac{m_{2}}{π}] V R T

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M_{2} = [\frac{m_{2}}{V}] \frac{R T}{π}

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M_{2} = [\frac{m_{2}}{π}] π R T

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M_{2} = [\frac{m_{2}}{V}] \frac{π}{R T}

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Solution

The correct option is A $M_{2} = [\frac{m_{2}}{V}] \frac{R T}{π}$
For dilute solution,
$p V = n R T$

or $π V = n R T$

or $π V = \frac{m_{2}}{M_{2}} R T$

or $M_{2} = \frac{m_{2} R T}{π V}$

where, $π$ = osmotic pressure

V =volume of solution

n = number of moles of solute

$m_{2}$ = mass of solute

$M_{2}$ = molecular mass of solute

Hence, option B is correct.

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A solution contains non- volatile solute of molecular mass M2. Which of the following can be used to calculate the molecular mass of solute in terms of osmotic pressure ?

The correct option is A M2=[m2V]RTπFor dilute solution,pV=nRTor πV=nRTor πV=m2M2RTor M2=m2RTπVwhere, π = osmotic pressure V =volume of solution n = number of moles of solutem2 = mass of soluteM2 = molecular mass of soluteHence, option B is correct.

A solution contains non- volatile solute of molecular mass $M_{2}$ . Which of the following can be used to calculate the molecular mass of solute in terms of osmotic pressure ?