A solution has an osmotic pressure of 0.821 atm at 300 K. Its concentration would be:

0.66

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0.32

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0.066

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0.033

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Solution

The correct option is D $0.033$ M
$π = C R T$
$C = π R T$
C= $\frac{0.821 a t m}{(0.0821 L a t m K^{- 1} m o l^{- 1}) \times 300 K}$
=0.0333 M
Hence, the correct option is $D$

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Osmotic pressure is 0.0821 atm at a temperature of 300 K. Find concentration in mole/litre.

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A solution has an osmotic pressure of 0.821 atm at 300 K. Its concentration would be:

The correct option is D 0.033 Mπ=CRTC=πRTC= 0.821 atm(0.0821 L atm K−1 mol−1)×300K=0.0333 MHence, the correct option is D

The correct option is D $0.033$ M
$π = C R T$
$C = π R T$
C= $\frac{0.821 a t m}{(0.0821 L a t m K^{- 1} m o l^{- 1}) \times 300 K}$
=0.0333 M
Hence, the correct option is $D$