A solution has been prepared by mixing $8.5 mL$ of ethanol with $80 mL$ of water. Calculate the volume percentage of the solution.

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Solution

Step-1: Calculate the volume of the solution
A solution comprises two parts i.e.; solute and solvent
Solute: The component of the solution to be dissolved or the component present in the solution in a lesser quantity.
Solvent: The component of the solution that dissolves or the component present in the solution in a larger quantity.
Here, Ethanol $(C_{2} H_{5} OH)$ is the solute and Water $(H_{2} O)$ is the solvent.
Given, Volume of the Ethanol (solute)= $8.5 mL$
Also, given, Volume of Water= $80 mL$
$Volume of solution = Volume of Ethanol (solute) + Volume of water (solvent)$
$Volume of solution = 8.5 + 80 = 88.5 mL$
Step-2: Calculate the volume percentage $(v / v)$ of Ethanol solution
Formula to be used:
$Concentration in (v / v) % = \frac{Volume of the solute (mL)}{Volume of the solution (mL)} \times 100$
$v / v$ represents volume by volume. It is a way to represent the concentration of the solution.
It is defined as the volume of the solute in $mL$ dissolved in per $100 mL$ of the solution.
Given, Volume of the Ethanol (solute)= $8.5 mL$
Given, Volume of the solution= $88.5 mL$ (calculated in Step 1)
Substituting the given values in the above formula
$Cancentration of Ethanol solution (v / v) % = \frac{8.5}{88.5} \times 100$
$Cancentration of Ethanol solution (v / v) % = \frac{8500}{885} = 9.60 %$
$Cancentration of Ethanol solution (v / v) % = 9.60 % (v / v)$

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