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Question

A solution is made with Solvent A (molar mass 40 g/mol) by slowly adding solute B. A curve is plotted between molality of the solution vs xBxA where xB and xA represents the mole fraction of solute and solvent respectively.
Calculate the slope of the curve.

A
10 mol/g
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B
10 g/mol
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C
25 g/mol
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D
25 mol/g
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Solution

The correct option is D 25 mol/g
Molality is given by
m=1000×nBnA×mA (i)
Where nA and nB are moles of solvent and solute respectively and MA is molar mass of solvent in g/mol
Also mole fraction of the solute is given by
xB=nBnA+nB (ii)
Substituting the value of nA from eq (ii)
we will get
m=1000MA×xBxA
slope=1000MA=25 mol/g


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