Question

A solution is obtained by mixing $200$ g of $30$% and $300$ g of $20$% solution by weight. What is the percentage of solute in the final solution?

• A. $50$%
• B. $28$%
• C. $64$%
• D. $24$%

Answer 1

Answer: (D)

$24$%

200 g of $30\%$ solution contains sloute=$\frac{200\times 30}{100}$=60

300 g $40\%$ solution contains solute=$\frac{300\times 20}{100}$=60

total solute=$60+60$

$=120$

As given in the question

total solution=$200+300$

$=500$

$\%$ of solute in the final solution=$\frac{120\times 100}{500}$$

$=24\%$

Hence, the correct option is $\text{D}$