A solution is prepared by dissolving $2 g m$ molecule of urea in $400 m l$ water at $30^{o}$ . What is mass percent urea in solution. The density of water at $30^{o} C$ is $1.2 g / m l$

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Solution

Given density $= 1.2$ g/ml
Mass of urea $= 2$ gm
Volume of solution= $400$ ml
Density=Mass/ volume
Mass= $1.2 \times 400 = 480$ g
$M a s s p e r c e n t a g e o f u r e a = \frac{M a s s o f u r e a}{M a s s o f s o l u t i o n} \times 100$
= $\frac{2}{480} \times 100 = 0.42$

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