A solution is prepared by dissolving $24.5 g$ of sodium hydroxide in distilled water to give $1 L$ solution. The molarity of $N a O H$ in the solution is :

0.2450 M

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0.6125 M

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0.9800 M

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1.6326 M

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Solution

The correct option is D $0.6125 M$
Given $W_{N a O H} = 24.5 g$
No. of moles of $N a O H = \frac{24.5}{40} m o l e s$
$= 0.6125 m o l e s$
$∴$ Molarity of solution
$= \frac{0.6125 m o l e s}{1 L} = 0.6125 M$

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A solution is prepared by dissolving 24.5 g of sodium hydroxide in distilled water to give 1 L solution. The molarity of NaOH in the solution is :

The correct option is D 0.6125 MGiven WNaOH=24.5 gNo. of moles of NaOH=24.540moles=0.6125 moles∴ Molarity of solution=0.6125 moles1 L=0.6125 M

A solution is prepared by dissolving $24.5 g$ of sodium hydroxide in distilled water to give $1 L$ solution. The molarity of $N a O H$ in the solution is :

The correct option is D $0.6125 M$
Given $W_{N a O H} = 24.5 g$
No. of moles of $N a O H = \frac{24.5}{40} m o l e s$
$= 0.6125 m o l e s$
$∴$ Molarity of solution
$= \frac{0.6125 m o l e s}{1 L} = 0.6125 M$