a solution is prepared by dissolving 28g of a substance x (molar mass= 65gmol-1) in 137g of substance y (molar mass=18 gmol-1). what are the mole fractions of x and y?

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Solution

Dear student,

Moles = $\frac{M a s s}{M o l a r m a s s}$
Moles of substance X = $\frac{28}{65} = 0.43 m o l e s$
Moles of substance Y = $\frac{137}{18} = 7.61$
Mole fraction of X = $\frac{M o l e s o f X}{T o t a l M o l e s} = \frac{0.43}{0.43 + 7.61} = 0.0534$
Mole fraction of Y = 1 - mole fraction of X = 1- 0.0534
Mole fraction of Y = 0.9465

Regards

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a solution is prepared by dissolving 28g of a substance x (molar mass= 65gmol-1) in 137g of substance y (molar mass=18 gmol-1). what are the mole fractions of x and y?

Dear student, Moles = MassMolar mass Moles of substance X = 2865= 0.43 moles Moles of substance Y = 13718=7.61 Mole fraction of X = Moles of XTotal Moles= 0.430.43 + 7.61= 0.0534 Mole fraction of Y = 1 - mole fraction of X = 1- 0.0534 Mole fraction of Y = 0.9465 Regards