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Molality

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Question

A solution is prepared by dissolving $4 g$ of NaOH to give $500 m l$ of it. Calculate the molality of the solution.

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Solution

Moles of NaOH $= \frac{m a s s}{m o l a r m a s s} = \frac{4}{40} = 0.1$
$500 m l \approx 500 g$
molality= $\begin{matrix} = \frac{m o l e s o f s o l u t e}{m a s s o f s o l v e n t (k g)} = \frac{0.1 \times 1000}{500} \end{matrix}$
$m = 2$

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