Question

A solution is prepared by dissolving 5.64 g of glucose in 60 g of water. Calculate the mole fraction of each of glucose and water respectively.

• A. 0.88, 0.12
• B. 0.009, 0.991
• C. 1.12, 0.08
• D. 0.789, 0.211

Answer 1

Answer: (B)

0.009, 0.991

$X_1$ $=molefractionofglucose$

$X_2$ $=molefractionofwater$

$n_1$ $=no.ofmolesofglucose$

$n_2$ $=no.ofmolesofwater$

Mole fraction of glucose $\left(X_1\right)=\frac{n_1}{n_1+n_2}$

$=\frac{\left(\frac{5.64}{180}\right)}{\left(\frac{5.64}{180}\right)+\left(\frac{60}{18}\right)}$

$=0.009$

Mole fraction of water $\left(X_2\right)=\frac{n_2}{n_1+n_2}$

$=\frac{\left(\frac{60}{18}\right)}{\left(\frac{5.64}{180}\right)+\left(\frac{60}{18}\right)}$

$=0.991$

Hence, option (B) is the correct answer.