A solution is saturated with SrCO 3 and SrF 2- The - CO 32- is found to be 1-2 - 10-3 M- if the value of solublity product of SrCO 3 and SrF 2 are 7-0 - 10-10 and 7-9 - 10-9 resectively-The concentration of F -in the solution would beA- 3-7 - 10-6 MB- 3-2 - 10-3 M- 3-7 - 10-2 MD- 5-1 - 10-7 M

The correct option is C 3.7 × 10^ 2M nbsp; It is AB_2 type salt, ∴ K_SP = 4S^3 (7.9 × 10^ 10 = 1.2 × 10^ 3× [F^ ]^2) ∵ [Sr^2+] = [CO_3^2 ] = 1.2 × 10^ 3M ∴ [ ...

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Standard XII

Chemistry

Factors Affecting Alpha

A solution is...

Question

A solution is saturated with $S r C O_{3}$ and $S r F_{2}$ . The $[C O_{3}^{2 -}]$ is found to be $1.2 \times 10^{- 3} M .$ if the value of solublity product of $S r C O_{3}$ and $S r F_{2}$ are $7.0 \times 10^{- 10} a n d 7.9 \times 10^{- 9}$ resectively.The concentration of $F^{-}$ in the solution would be

3.7 \times 10^{- 6} M

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3.2 \times 10^{- 3} M

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5.1 \times 10^{- 7} M

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3.7 \times 10^{- 2} M

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Solution

The correct option is D $3.7 \times 10^{- 2} M$
It is $A B_{2}$ type salt,
$∴ K_{S P} = 4 S^{3}$
$(7.9 \times 10^{- 10} = 1.2 \times 10^{- 3} \times [F^{-}]^{2}) ∵ [S r^{2 +}] = [C O_{3}^{2 -}] = 1.2 \times 10^{- 3} M$
$∴ [F^{-}] = 3.7 \times 10^{- 2} M$

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Similar questions

Q. A solution is saturated with respect to

S r C O_{3}

and

S r F_{2}

. The

[C O_{3}^{2 -}]

was found to be

1.2 \times 10^{- 3} M

. The values of the solubility products of

S r C O_{3}

and

S r F_{2}

are

7.0 \times 10^{- 10}

and

7.9 \times 10^{- 10}

respectively. The concentration of

F^{-}

in the solution would be:

Q. A solution is saturated with respect to

S r {C O}_{3}

and

S r F_{2}

. The

{C O}_{3}^{2 -}

was found to be

1.2 \times 10^{- 3} M

. The concentration of

F^{-}

in the solution would be:

Q. A solution is saturated with respect to strontium fluoride and strontium carbonate. The fluoride ion concentration in the solution is found to be

3.7 \times 10^{- 2} m o l L^{- 1}

. What is the value of

[{C O}_{3}^{2 -}]

?
(

K_{s p} : S r F_{2} = 7.9 \times 10^{- 10}; K_{s p} : S r {C O}_{3} = 7.0 \times 10^{- 10}

)

Q. Calculate

[F^{-}]

in a solution saturated with respect to both

M g F_{2}

and

S r F_{2}

assuming no hydrolysis of

F^{-}

K_{s p}

M g F_{2} = 6.5 \times 10^{- 9}

;

K_{s p}

S r F_{2} = 2.9 \times 10^{- 9}

Q. Calculate

[F^{-}]

in a solution saturated with respect to both

M g F_{2}

and

S r F_{2}

K_{s p} (M g F_{2}) = 9.5 \times 10^{- 9}

K_{s p} (S r F_{2}) = 4 \times 10^{- 9}

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A solution is saturated with SrCO3 and SrF2. The [CO2−3] is found to be 1.2×10−3M. if the value of solublity product of SrCO3 and SrF2 are 7.0×10−10 and 7.9×10−9 resectively.The concentration of F− in the solution would be

The correct option is D 3.7×10−2M It is AB2 type salt, ∴KSP=4S3 (7.9×10−10=1.2×10−3×[F−]2)∵[Sr2+]=[CO2−3]=1.2×10−3M ∴[F−]=3.7×10−2M

The correct option is D $3.7 \times 10^{- 2} M$
It is $A B_{2}$ type salt,
$∴ K_{S P} = 4 S^{3}$
$(7.9 \times 10^{- 10} = 1.2 \times 10^{- 3} \times [F^{-}]^{2}) ∵ [S r^{2 +}] = [C O_{3}^{2 -}] = 1.2 \times 10^{- 3} M$
$∴ [F^{-}] = 3.7 \times 10^{- 2} M$