A solution is separated from pure solvent by a semipermeable membrane at 298 K. The difference in the height of the solution and the solvent is 0.9 m. If Kf and freezing point of the solvent are 30 K kg mol1 and 250.3 K, respectively, the temperature at which the solution freezes is: (a) 250.10 K (c) 250.20 K (ISAT 2010) (b) 250.25 K (d) 250.05 K

Open in App

Solution

Suggest Corrections

Similar questions

Assertion (A) When a solution is separated from the pure solvent by a semipermeable membrane, the solvent molecules pass through it from pure solvent side to the solution side.
Reason (R) Diffusion of solvent occurs from a region of high concentration solution to a region of low concentration solution.

Q. A solution which has

10 g

of solvent and

0.20 g

of solute (mol. mass 122 g/mol) freezes at

{0.5}^{\circ} C

below the freezing point of pure solvent. If the solute exists as dimer in the solvent, choose the correct option :

(K_{f})_{solvent} = 5.12 K k g^{- 1} m o l^{- 1}

Here,

i = Van't hoff factor β = Degree of association

The process of movement of solvent through a semipermeable membrane from the solution to the pure solvent by applying excess pressure on the solution side is called

Q. A solvent X freezes at