Question

A solution is to be kept between ${30}^{\circ }Cand{35}^{\circ }C$.What is the range of temperature in degree Fahrenheit ?

Answer 1

We have,

$C_1={30}^{\circ }C\therefore F_1=\frac{9}{5}{C}_1+32[\because F=\frac{9}{5}C+32]\Rightarrow F_1=\frac{9}{5}\times 30+32\Rightarrow F_1=9\times 6+32\Rightarrow F_1=54+32\Rightarrow F_1={86}^{\circ }FNow,C_2={35}^{\circ }C\therefore F_2=\frac{9}{5}{c}_2+32\Rightarrow F_2=\frac{9}{5}\times 35+32\Rightarrow F_2=9\times 7+32\Rightarrow F_2=63+32\Rightarrow F_2={95}^{\circ }F$

$\therefore$ Hence,the temperature of the solution lies between ${86}^{\circ }Fto{95}^{\circ }F.$