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Question

A solution of 0.1MKMnO4 is used for the reaction, S2O23+2MnO4+H2OMnO2+SO24+OH. What volume of solution in mL will be required to react with 0.158g of Na2S2O3? (in mL as nearest integer)

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Solution

The redox changes are as follows:
(S2+)22S6++8e [ENa2S2O3=M8]
Mn7++3eMn4+ ('n' factor for KMnO4=3)
Meq.ofKMnO4=Meq.ofS2O23
0.1×3×V=0.1581588×1000

V=26.67mL
So, the nearest integer value is 27 mL.

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