A solution of 2% (by mass) sodium chloride is prepared. The molality of this solution is:

0.483

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0.393

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0.349

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0.750

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Solution

The correct option is D $0.349$
2%( by mass) means 2 gm solute in 100 gm solution i.e. 98 gm of solvent.

molality $= \frac{2}{58.5} \times \frac{1000}{98}$

$= 0.349$
Option C is correct.

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A solution contains 20 g of sodium chloride dissolved in 80 g of water. The concentration of this solution by mass percentage method is

1

N a C l

58.5 g

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