Question

A solution of A and B follows Raoult's law and vapour pressure of solution (P) can be represented as $\frac{P}{cmofHg}=92-22x$
Here 'x' is the mole fraction of liquid A in the solution then what will be the vapour pressure of 'B' in pure form?

• A. 92 atm
• B. 70 atm
• C. 92 cm of Hg
• D. 70 cm of Hg

Answer 1

The correct option is C 92 cm of Hg

$\frac{P}{cmofHg}=92-22x$
Let x = 0 $\therefore$ 'B' is present in pure form
$P_B^{\circ }=92cmofHg$.