Question

A solution of A, when treated with $N{H}_3$ gives________.

• A. a white precipitate soluble in an excess of $N{H}_3$
• B. a white precipitate insoluble in an excess of $N{H}_3$
• C. a grey precipitate soluble in an excess of $N{H}_3$
• D. a grey precipitate insoluble in an excess of $N{H}_3$

Answer 1

The correct option is B a white precipitate insoluble in an excess of $N{H}_3$

With ammonia solution, $P{b}^{2+}$ gives a white precipitate of lead hydroxide

$P{b}^{+2}+2N{H}_{4}OH⟶\underset{WhitePPT}{Pb(OH{)}_2+2N{H}_4^{+}}$

The precipitate is insoluble in excess reagent $\left(N{H}_{4}OH\right)$