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Elevation in Boiling Point

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Question

A solution of an organic compound is prepared by dissolving $34.2$ g in $500$ g of water. Calculate the molar mass of the compound Given that $K_{b}$ for water $= 1.87$ K $m o l^{- 1}$ .
Boiling point of solution $= {100.104}^{o}$ C. (Write up to 2 decimal places.)

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Solution

$K_{b}$ of water $= 1.87$
morality of solute $= \frac{34.2}{m \times 500 / 1000} = \frac{342 \times 2}{m}$
( $∵$ morality : mole of solute mass of solvent (kg)) (m = m: water of solute)
Elevation in boiling point = morality $\times K_{b}$
Elevation $= 100.104 - 100 = 0.104$
So $.104 = \frac{34.2 \times 2}{m} = m = 1229.88$

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