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Van't Hoff Factor

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Question

A solution of benzoic acid dissolved in benzene such that it undergoes molecular association and its molar mass approaches 244. Benzoic acid molecules will exist as :

A

dimer

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B

monomer

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C

tetramer

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D

trimer

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Solution

The correct option is A dimer
Molecular weight of Benzoic acid $= 122$ and now new molecule has $M \cdot w t = 244$
So, new $M \cdot w t = \frac{1}{2} M \cdot w t$ of Benzoic acid
So, it exists as a dimer.

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Similar questions

The electrolyte solutions show abnormal colligative properties. To account for this effect we define a quantity called the Van't Hoff factor given by :

i = \frac{Actual number of particles in solution after dissociation/association}{Number of formula units initially dissolved in solution}

i = 1

(for non-electrolytes)

i > 1

(for non-electrolytes, undergoing dissociation)

i < 1

(for solutes, undergoing dissociation)

Answer the following questions:

A solution of benzoic acid is dissolved in benzene such that it undergoes molecular association and its molar mass approaches 244. The benzoic molecules will exist as :

Q. If benzoic acid (mol. mass = 122) is associated into double molecules when dissolved in benzene and the osmotic pressure of a solution of 5 g of benzoic acid in 100 mL benzene is 5.73 atm at

10^{o} C

, what is the percentage association of benzoic acid?

Q. Assertion :The molar mass obtained for benzoic acid in benzene is found to be nearly 244. Reason: Benzoic acid has the molecular formula

C_{6} H_{6} O_{2}

Q. Benzoic acid undergoes dimerization to

60

percent in benzene. The observed mass of benzoic acid will be:

Q. Benzoic acid (molecular weight

= 122

^{- 1}

) associates to form dimer when dissolved in benzene and the osmotic pressure of a solution of

5

g of benzoic acid in

100

5.73

10^{o} C

. What is the percentage association of benzoic acid?

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