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Standard XII

Chemistry

Sulphuric Acid

A solution of...

Question

A solution of colorless salt H on boiling with excess NaOH produces a non-flammable gas. The gas evolution ceases after sometime upon addition of Zn dust to the same solution, the gas evolution restarts. The colourless salt(s) H is(are) :

N H_{4} N O_{3}

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N H_{4} N O_{2}

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N H_{4} C l

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(N H_{4})_{2} S O_{4}

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Solution

The correct options are
B $N H_{4} N O_{2}$
C $N H_{4} N O_{3}$
Option (A), (B) are correct.
The colorless salt H is either $N H_{4} N O_{3}$ or $N H_{4} N O_{2}$ . The colorless salt produces $N H_{3}$ gas (non-inflammable) on boiling with excess of $N a O H$ . On addition of zinc dust (a reducing agent) to this solution, sodium nitrite or sodium nitrate will liberate $N H_{3}$ gas again.
$N H_{4} N O_{3} + N a O H ⟶ N H_{3} + N a N O_{3} + H_{2} O$
$7 N a O H + N a N O_{3} + 4 Z n ⟶ 4 N a_{2} Z n O_{2} + N H_{3} + 2 H_{2} O$

$N H_{4} N O_{2} + N a O H ⟶ N a N O_{2} + N H_{3} + H_{2} O$
$3 Z n + 5 N a O H + N a N O_{2} ⟶ 3 N a_{2} Z n O_{2} + N H_{3}$

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