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Question

A solution of copper sulphate in which copper rod is immersed is diluted to 10 times the reduction electrode potential is a) increases by 0.030 volt b) decreases by 0.030 volt c) increases by 0.059 volt d) decreases by 0.059 volt

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Solution

Dear Student,

The computation is expressed below,

Nernst equation for the given is,Cu2+ + 2e- CuE=Eo+0.0592log[Cu2+]by decrasing [Cu2+] by 10 times is 1 10 E value which is 0.0592=0.295is approx 0.03 V decrease.Hence answer is Option (B)decrease by 0.030 V

Regards.

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