Question

A solution of $Cu\left(II\right)$ sulphate is reacted with $KCl$ and $KI$. In which case will the $C{u}^{2+}$ be reduced to $C{u}^{+}$?

• A. In both the cases
• B. When reacted with $KCl$
• C. When reacted with $KI$
• D. In both the cases but in presence of $H^{+}$

Answer 1

The correct option is A In both the cases

The reduction potential of Cu (0.34)is more more than that of K (-2.93),

so, in both the cases the reduction of $C{u}^{2+}$ ions takes place.