A solution of CuSO4 is electrolysed for 7 minutes with a current of 0.6A. The amount of electricity passed is equal to:
A
4.2C
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B
2.6×10−3F
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C
126C
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D
36C
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Solution
The correct option is B2.6×10−3F Quantity of electricity passed Q(C)=I(A)×t(s) Q(C)=0.6A×7min×60s/min Q(C)=252C Number of faraday passed =252C96500C/F=2.6×10−3F