Question

A solution of $CuS{O}_4$ is electrolysed for $7$ minutes with a current of $0.6A$. The amount of electricity passed is equal to:

• A. $4.2C$
• B. $2.6\times {10}^{-3}F$
• C. $126C$
• D. $36C$

Answer 1

The correct option is B $2.6\times {10}^{-3}F$

Quantity of electricity passed $Q\left(C\right)=I\left(A\right)\times t\left(s\right)$
$Q\left(C\right)=0.6A\times 7min\times 60s/min$
$Q\left(C\right)=252C$
Number of faraday passed $=\frac{252C}{96500C/F}=2.6\times {10}^{-3}F$