Question

A solution of ${CuSO}_4$ is electrolyzed for $10$ minutes with a current of $1.5$ amperes. What is the mass of copper deposited at the cathode?

• A. $0.396g$
• B. $0.296g$
• C. $0.186g$
• D. $0.346g$

Answer 1

Answer: (B)

$0.296g$

The cathode reaction is:

${Cu}^{2+}+2e^{-}\to Cu$

Given that,

$I=1.5$ amperes

$t=10\times 60=600$ sec

Now,

$Q=It=1.5\times 600=900C$

$(2\times 96500)C$ are required to deposit $63.5g$ of $Cu$ at cathode.

$900C$ will deposit $\frac{63.5\times 900}{2\times 96500}=0.296g$ of $Cu$ at cathode.