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Depression in Freezing Point

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Question

A solution of ester in benzene freezes at $0.84 K$ temperature, blow the freezing point of the solution. What is the molality of the solution if $k_{f}$ of benzene is $5.12 K k g m o l^{- 1}$ ?

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Solution

Given $k_{f}$ $= 5.12 k g$ ${m o l}^{- 1}$
$Δ T_{f}$ $= 0.84 K$
$Δ T_{f} = k_{f} \times m$
where $m$ is the molality
$m = \frac{0.84}{5.12} = 0.16 m o l / k g$

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