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Based on the Type of Solvent

A solution of...

Question

A solution of $F e S O_{4}$ in water is:
(a) colourless
(b) blue
(c) light green
(d) brown

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Solution

Colourless

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What happens to the colour of bromine water when $S O_{2}$ is passed into the solution?

State True or False.

N O_{3}^{-}

solution produce brown ring with

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H_{2} S O_{4}

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Q. The reaction of

K_{3} [F e (C N)_{6}]

with freshly prepared

F e S O_{4}

solution produces a dark blue precipitate called Turnbull’s blue. Reaction of

K_{4} [F e (C N)_{6}]

F e S O_{4}

solution in complete absence of air produces a white precipitate

X

, which turns blue in air. Mixing the

F e S O_{4}

N a N O_{3},

followed by a slow addition of concentrated

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through the side of the test tube produces a brown ring.

Among the following, the brown ring is due to the formation of

Q. The colour of light absorbed by an aqueous solution of

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solution gives a brown coloured ring during the test for nitrates or nitrites. This due to the formation of:

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Based on the Type of Solvent

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