A solution of glucose in water is 5% by mass. How much glucose is present in 400g of the solution?

Open in App

Solution

Step 1: Given:
The mass percentage of the glucose solution $= 5 %$ by mass.
Mass of the glucose solution $= 400 g$
Step 2: Formula:
$Mass percentage of a solution = \frac{Mass of solute}{Mass of solution} \times 100$
Step 3: Finding the amount of solute in the solution:
The mass percentage is defined as the mass of solute present in 100g of solution.
$Mass percentage of a solution = \frac{Mass of solute}{Mass of solution} \times 100$
Putting the given values in the above formula. Here, the solute is glucose.
$5 = \frac{Mass of glucose}{400 g} \times 100$
$5 = \frac{Mass of glucose}{4} Mass of the glucose = 20 g$
Therefore, $400 g$ of the given solution contains $20 g$ of glucose.

Suggest Corrections

Similar questions

A solution is prepared by dissolving 11g glucose in 200 cm³ water at 30⁰c. What is the mass percentage of glucose in solution ? The density of water at 30⁰c is 0.996g /cm³?

A solution is prepared by dissolving 50 g of glucose in 400 g of water. Calculate the concentration of the solution.

Q. A

5

% solution (by mass) of cane sugar in water has freezing point of

271 K

and freezing point of pure water is

273.15 K

. The freezing point of a

5

% solution (by mass) of glucose in water is :

Q. A solution is prepared by dissolving

11 g

glucose in

250 c m^{3}

water at

30^{o} C

. what is mass percent glucose in solution. The density of water at

30^{o}

0.996 g / c m^{3}

A solution is prepared by dissolving 5.64 g of glucose in 60 g of water. Calculate the mass percent of glucose.

Join BYJU'S Learning Program