A solution of glucose $(C_{6} H_{12} O_{6})$ in water is labelled as 10% by weight. What would be the molality of the solution?
(Molar mass of glucose = 180 g mol $^{- 1}$ )

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Solution

The correct option is A 0.6
Molality of a solution is defined as the number of moles of solute dissolved per kg of solvent.

$C_{6} H_{12} O_{6}$ =10% by weight.

Thus in 100 g solution mass of glucose = 10 g and of water =90 g

$N u m b e r o f m o l e s o f g l u c o s e = \frac{m a s s}{m o l a r m a s s}$

$n = \frac{10}{180} = \frac{1}{18} m o l$

Mass of solvent = 90 g= 0.09 kg

Molality, $m = \frac{(\frac{1}{18})}{0.09}$

$m = \frac{100}{18 \times 9} = 0.617 m o l a l \approx 0.6 m o l a l$

The molality of a solution of glucose ( $C_{6} H_{12} O_{6}$ ) in water is labelled as 10% by weight is 0.617 molal.

Hence, the correct option is $(B)$

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A solution of glucose (C6H12O6) in water is labelled as 10% by weight. What would be the molality of the solution?(Molar mass of glucose = 180 g mol−1)

A solution of glucose $(C_{6} H_{12} O_{6})$ in water is labelled as 10% by weight. What would be the molality of the solution?
(Molar mass of glucose = 180 g mol $^{- 1}$ )