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Question

# A solution of H2C2O4 requires 200ml of NaOH for complete neutralization. The pH of the solution when 120ml of NaOH is added is: (Given :Ka1=10âˆ’4 and Ka2=10âˆ’7 for H2C2O4)[log2=0.30]

A
3.4
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B
4.6
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C
5.6
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D
6.4
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Solution

## The correct option is A 6.4One mole of H2C2O4 requires 2 moles of NaOH for complete neutralization. Thus, when 120 ml is used:H2C2O4+NaOH→NaHC2O4+H2O100x 200x 0 0 100x 100x Again,NaHC2O4+NaOH→Na2C2O4 100x 20x 0 80x 0 20x∴pH=pKa2+log20x80x=−log(10−7)+log14 ∴pH=6.4

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