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A solution of $H C l$ has a $p H = 5$ . If $1 m L$ of it is diluted to $1$ litre, what will be the pH of the resulting solution?

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Solution

$p H = 5, [H^{+}] = 10^{- 5}$
after dilution
$= \frac{10^{- 5}}{1000} = 10^{- 8} M$
$[H^{+}] = 10^{- 8} + 10^{- 7}$
$p H = - log [H^{+}]$
$p H = 6.9586$

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