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Molarity

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Question

A solution of $K M n O_{4}$ is reduced to $M n O_{2}$ . The normality of solution is $0.6$ . The molarity is:

A

1.8

M

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B

0.6

M

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C

0.1

M

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D

0.2

M

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Solution

The correct option is D $0.2$ M
$N o r m a l i t y = M o l a r i t y \times V a l a n c y f a c t o r$
$0 .6 = M \times 3$
$M = \frac{0.6}{3} = 0.2$
The correct option is option $[D]$ .

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