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Byju's Answer
Standard XII
Chemistry
Relative Lowering of Vapour Pressure
A solution of...
Question
A solution of lactose containing 8.45 g of lactose in 100 g of water has a vapour pressure of 4.559 mm of Hg at 0
o
C. If the vapour pressure of pure water is 4.579 mm of Hg, calculate the molecular weight of lactose.
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Solution
Given : Weight of lactose w
=
8.45
g
Weight of water W
=
100
g
Vapour pressure of pure water
=
4.579
m
m
of Hg
Vapour pressure of solution
=
4.559
m
m
of Hg
Now, according to Roast's law.
Δ
P
P
=
w
×
M
m
×
W
4.579
−
4.559
4.579
=
8.45
×
18
m
×
100
m
=
8.45
×
18
×
4.579
0.02
×
100
=
348.23
≈
348
Molecular mass of lactose is 348.
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Relative Lowering of Vapour Pressure
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