CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
205
You visited us 205 times! Enjoying our articles? Unlock Full Access!
Question

A solution of m-chloroaniline, m-chlorophenol, m-chlorobenzoic acid in ethyl acetate was extracted initially with a saturated solution of NaHCO3 to give fraction A. The leftover organic phase was extracted with dilute NaOH to give fraction B. The final organic layer was labelled as fraction C. Fractions A, B and C, contain respectively:

A
m-chlorophenol, m-chlorobenzoic acid and m-chloroaniline
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
m-chlorobenzoic acid, m-chlorophenol and m-chloroaniline
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
m-chloroaniline, m-chlorobenzoic acid and m-chlorophenol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
m-chlorobenzoic acid, m-chloroaniline and m-chlorophenol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B m-chlorobenzoic acid, m-chlorophenol and m-chloroaniline
m-chlorobenzoic acid being the most acidic can be separated by a weak base like NaHCO3 and hence will be labelled fraction A.

m-chlorophenol is not as acidic as m-chlorobenzoic acid, and can be separated by a stronger base like NaOH, and hence can be labelled as fraction B.

m-chloroaniline being a base, does not react with either of the bases and hence would be labelled as fraction C.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Reactions of Haloalkanes
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon