A solution of $N a O H$ (Molar mass $40 g {m o l}^{- 1})$ was prepared by dissolving $1.6 g$ of $N a O H$ in $500 c m^{3}$ of water. Calculate molarity of $N a O H$ solution.

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Solution

$1$ mol of $N a O H$ has a mass of $40 g$ . So
Moles of $N a O H = 1.6 g$ of $N a O H \times \frac{1 m o l N a O H}{40 g N a O H} = 0.04$ mol $N a O H$
Litres of solution $= 500 m l$ solution $\times \frac{1 L S o l u t i o n}{1000 m l S o l u t i o n} = 0.5$ $L$ Solution
Molarity $= \frac{m o l e s o f S o l u t e}{l i t r e s o f s o l u t i o n}$
$= \frac{0.04}{0.5}$ mol/L
$= 0.08$ mol/L

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