A solution of naphthalene in benzene is $2$ percent by mass in naphthalene. What is mass percent benzene?

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Solution

Mass % of $C_{6} H_{6} = \frac{M a s s o f C_{6} H_{6}}{T o t a l m a s s o f s o l u t i o n} X 100$

$= \frac{M a s s o f C_{6} H_{6}}{M a s s o f C_{6} H_{6} + M a s s o f C C l_{4}} X 100$

$= \frac{22}{22 + 122} X 100$

$= 15.28$ is the answer.

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QUESTION 2.38

Benzene and naphthalene form ideal solution over the entire range of composition. The vapour pressure of pure benzene and naphthalene at 300 K are 50.71 mm Hg and 32.06 mm Hg respectively. Calculate the mole fraction of benzene in vapour phase if 80 g of benzene is mixed with 100 g of naphthalene.

Q. Naphthalene contain how many benzene ring in the structure?

Q. Find the boiling point of a solution of 5.00 g of naphthalene

(C_{10} H_{8})

in 100 g of benzene.

K_{b}

of benzene = 2.53

^{o}

C/m; the normal boiling point of benzene = 80

^{o}

Q. Benzene and naphthalene from an ideal solution at room temperature. For this process, the true statement(s) is (are)

Q. Benzene and naphthalene form an ideal solution at room temperature. For this process, the true statement(s) is(are):

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A solution of naphthalene in benzene is 2 percent by mass in naphthalene. What is mass percent benzene?

Mass % of C6H6=MassofC6H6TotalmassofsolutionX100=MassofC6H6MassofC6H6+MassofCCl4X100=2222+122X 100=15.28 is the answer.

A solution of naphthalene in benzene is $2$ percent by mass in naphthalene. What is mass percent benzene?

Mass % of $C_{6} H_{6} = \frac{M a s s o f C_{6} H_{6}}{T o t a l m a s s o f s o l u t i o n} X 100$

$= \frac{M a s s o f C_{6} H_{6}}{M a s s o f C_{6} H_{6} + M a s s o f C C l_{4}} X 100$

$= \frac{22}{22 + 122} X 100$

$= 15.28$ is the answer.