A solution of PH= 9 is 1000 times as basic as PH?

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Solution

pH = - log(H+)
9 = - log(H+)
10^(-9)= H+
we need to find less basic solution,i.e. more acidic so more H+ concentration in the new solution.
so
H+ in new solution = 10^(-9) * 1000 = 10(-6)

pH of new solution = -log(10^(-6)) = 6

so pH 9 is 1000 times more basic than pH 6.

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A solution of PH= 9 is 1000 times as basic as PH?

pH = - log(H+) 9 = - log(H+) 10^(-9)= H+ we need to find less basic solution,i.e. more acidic so more H+ concentration in the new solution. so H+ in new solution = 10^(-9) * 1000 = 10(-6) pH of new solution = -log(10^(-6)) = 6 so pH 9 is 1000 times more basic than pH 6.

pH = - log(H+)
9 = - log(H+)
10^(-9)= H+
we need to find less basic solution,i.e. more acidic so more H+ concentration in the new solution.
so
H+ in new solution = 10^(-9) * 1000 = 10(-6)

pH of new solution = -log(10^(-6)) = 6

so pH 9 is 1000 times more basic than pH 6.