A solution of potassium chloride in water is $35 % (m / v)$ . The density of the solution is $1.2 g {mL}^{- 1}$ . Calculate the concentration of the solution in $% (m / m)$

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Solution

Step-1: Calculate the mass of the given solution
It is given that solution of Potassium chloride $(KCl)$ has a concentration of $35 % (m / v)$ .
$m / v$ represents mass by volume. It is a way to represent the concentration of the solution.
It is defined as the mass of the solute in $g$ dissolved in per $100 mL$ of the solution.
$35 % (m / v)$ can be interpreted as $35 g$ of Potassium chloride (solute) is present in $100 mL$ of the solution according to the formula given below:
A solution comprises two parts i.e.; solute and solvent
Solute: The component of the solution to be dissolved or the component present in the solution in a lesser quantity.
Solvent: The component of the solution that dissolves or the component present in the solution in a larger quantity.
$Concentration in (m / v) % = \frac{Mass of the solute (g)}{Volume of the solution (mL)} \times 100$ ……(i)
To calculate the concentration in $% (m / m)$ , the mass of the solution needs to be calculated first which can be done using the density of the solution.
$Density of the solution = \frac{Mass of the solution (g)}{Volume of the solution (mL)}$ ……..(ii)
Given, Density= $1.2 g {mL}^{- 1}$
The volume of the solution= $100 mL$ ……..interpreted from $(m / v)$
Substituting the values in the formula (ii)
$1.2 = \frac{Mass of the solution}{100}$
$Mass of the solution = 1.2 \times 100 = 120 g$
Step-2: Calculate the concentration of the solution in $% (m / m)$
The formula used to calculate the concentration in $% (m / m)$ is given below:
$Concentration in (m / m) % = \frac{Mass of the solute (g)}{Mass of the solution (g)} \times 100$
$m / m$ represents mass by mass. It is a way to represent the concentration of the solution.
It is defined as the mass of the solute in $g$ dissolved in per $100 g$ of the solution.
Mass of the solute= $35 g$ (interpreted above)
Mass of the solution= $120 g$ (calculated above)
$Concentration in (m / m) % = \frac{35}{120} \times 100 = \frac{3500}{120} = 29.167 %$
$Hence, concentration of the solution in (m / m) % = 29.167 % (m / m)$

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A solution of potassium chloride in water is 35%(m/v). The density of the solution is 1.2gmL-1. Calculate the concentration of the solution in %(m/m)

A solution of potassium chloride in water is $35 % (m / v)$ . The density of the solution is $1.2 g {mL}^{- 1}$ . Calculate the concentration of the solution in $% (m / m)$