A solution of SO $_{2}$ in water reacts with H $_{2}$ S precipitating sulphur. Here, SO $_{2}$ acts as :

an oxidising agent

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a reducing agent

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an acid

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a catalyst

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Solution

The correct option is B an oxidising agent
$S O_{2} + H_{2} S \to S + H_{2} O$

Oxidation number of S in $S O_{2} = + 4$

Oxidation number of S in $S = 0$

The oxidation state of sulphur changes from +4 to 0.

$∴ S O_{2}$ act as an oxidising agent.

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