A solution of SO 2 in water reacts with H 2 S precipitating sulphur- Here SO 2 acts asA- Oxidising agentB- Reducing agentC- AcidD- Catalyst

The correct option is A Oxidising agent2H_2S + SO_2 → 2H_2O + 3S ...

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Oxides of Sulphur

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A solution of $S O_{2}$ in water reacts with $H_{2} S$ precipitating sulphur. Here $S O_{2}$ acts as

Oxidising agent

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Reducing agent

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Acid

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Catalyst

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H_{2} S

S O_{2}

H_{2} S

S O_{2}

In the reaction $2 A g + 2 H_{2} S O_{4} \to A g_{2} S O_{4} + 2 H_{2} O + S O_{2}$ sulphuric acid acts as

C + H_{2} O ⟶ C O + H_{2}, H_{2} O

2 A g + 2 H_{2} S O_{4} \to A g_{2} S O_{4} + H_{2} O + S O_{2}

H_{2} S O_{4}

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