A solution of sodium bicarbonate in water turns

Phenolphthalein - Pink

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Methyl orange - yellow

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Methyl orange - Red

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Blue litmus - Red

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Solution

The correct option is C Methyl orange - Red
$N a H C O_{3} w a t e r - -- \to N a^{+} + H C O_{3}^{- 1}$
$N a H C O_{3}$ in water is alkaline, it turns methyl orange - Red

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Similar questions

	Indicator	Colour change in basic medium
(1)	Litmus paper	Red to blue
(2)	Methyl orange	Orange to red
(3)	Phenolphthalein	Colourless to pink
(4)	Turmeric	Yellow to reddish brown

\begin{matrix} A) L i t m u s & 1) B l u e i n a c i d i c, p i n k i n b a s i c s o i l s B) M e t h y l o r a n g e & 2) R e d i n a c i d i c, y e l l o w i n b a s i c s o l u t i o n s C) P h e n o l p h t h a l e i n & 3) B l u e i n b a s i c, r e d i n a c i d i c s o l u t i o n s D) C o l o r o f H y d r a n g e a & 4) P i n k i n b a s i c, c o l o r l e s s i n a c i d i c s o l u t i o n s \end{matrix}

\begin{matrix} a) Litmus & 1) Blue in acidic, pink in basic soils b) Methyl orange & 2) Red in acidic, yellow in basic solutions c) Phenolphthalein & 3) Blue in basic, red in acidic solutions d) Color of Hydrangea & 4) Pink in basic, colorless in acidic solutions \end{matrix}

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