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pH the Power of H

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Question

A solution of Sodium Hydroxide (NaOH) has a pH of 9. What will be the concentration of $O H^{-}$ ions?

10^{- 9} M

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10^{- 6} M

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10^{- 4} M

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10^{- 5} M

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Solution

The correct option is D $10^{- 5} M$
$W e k n o w p H + p O H = 14 9 + p O H = 14 \Rightarrow p O H = 14 - 9 = 5 p O H = - l o g_{10} [O H^{-}] = 5 [O H^{-}] = 10^{- 5} M$
Hence concentraion of $O H^{-}$ is $10^{- 5} M$

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