Question

A solution of sodium in liquid ammonia is strongly reducing and highly conducting due to :

• A. Sodium atoms
• B. Sodium hydride
• C. Sodium amide
• D. Solvated electrons

Answer 1

The correct option is D Solvated electrons

$M+(x+y)N{H}_3\to \left[M\right(N{H}_3{)}_x{]}^{+}+\left[e\right(N{H}_3{)}_y{]}^{-}$
So the solution contains unpaired solvated electrons which are responsible for their strongly reducing and highly conducting nature.