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Stoichiometric Calculations

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Question

A solution of sodium sulfate contains 92 g of $N a^{+}$ ions per kilogram of water. The molality of $N a^{+}$ ions in that solution in $m o l k g^{- 1}$ is:

A

16

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B

8

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C

4

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D

12

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Solution

The correct option is C 4
Molality $= \frac{no . of moles}{kilogram} = \frac{92}{23} \times 1 = 4$

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