Question

A solution of the equation $cose{c}^2\theta$ + $co{t}^2\theta$ = 3 is ....................

Answer 1

$cose{c}^2\theta$ + $co{t}^2\theta$ = 3

($\frac{1}{si{n}^2\theta }$) + ($\frac{co{s}^2\theta }{si{n}^2\theta }$) = 3

1 + $co{s}^2\theta$ = 3 $si{n}^2\theta$

we can replace 1 by $si{n}^2\theta$ + $co{s}^2\theta$

Thus the equation be comes.

$si{n}^2\theta$ + $co{s}^2\theta$ + $co{s}^2\theta$ = 3 $si{n}^2\theta$

$cos\theta$ = $sin\theta$

Thus, $\theta$ = ${45}^{\circ }$.